Information for RPM python-pycurl-7.19.0-17.el7.src.rpm
ID | 307 | |||||
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Build | python-pycurl-7.19.0-17.el7 | |||||
Name | python-pycurl | |||||
Version | 7.19.0 | |||||
Release | 17.el7 | |||||
Epoch | ||||||
Arch | src | |||||
Draft | False | |||||
Summary | A Python interface to libcurl | |||||
Description | PycURL is a Python interface to libcurl. PycURL can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features. | |||||
Build Time | 2014-06-10 08:55:55 GMT | |||||
Size | 89.69 KB | |||||
281e9fdc726d5394f715574b6aea87be | ||||||
License | LGPLv2+ or MIT | |||||
Provides | No Provides | |||||
Obsoletes | No Obsoletes | |||||
Conflicts | No Conflicts | |||||
Requires |
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Recommends | No Recommends | |||||
Suggests | No Suggests | |||||
Supplements | No Supplements | |||||
Enhances | No Enhances | |||||
Files | ||||||
Component of | No Buildroots |