Information for RPM python-pycurl-7.19.0-19.el7.src.rpm
| ID | 3943 | |||||
|---|---|---|---|---|---|---|
| Build | python-pycurl-7.19.0-19.el7 | |||||
| Name | python-pycurl | |||||
| Version | 7.19.0 | |||||
| Release | 19.el7 | |||||
| Epoch | ||||||
| Arch | src | |||||
| Draft | False | |||||
| Summary | A Python interface to libcurl | |||||
| Description | PycURL is a Python interface to libcurl. PycURL can be used to fetch objects identified by a URL from a Python program, similar to the urllib Python module. PycURL is mature, very fast, and supports a lot of features. | |||||
| Build Time | 2016-11-05 15:10:22 GMT | |||||
| Size | 92.17 KB | |||||
| cdea2358016e6b42ac01e251d3fddcea | ||||||
| License | LGPLv2+ or MIT | |||||
| Provides | No Provides | |||||
| Obsoletes | No Obsoletes | |||||
| Conflicts | No Conflicts | |||||
| Requires |
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| Recommends | No Recommends | |||||
| Suggests | No Suggests | |||||
| Supplements | No Supplements | |||||
| Enhances | No Enhances | |||||
| Files | ||||||
| Component of | No Buildroots |

